Mercurial > hg > euler
view problem29.py @ 14:49c96972949d default tip
#50 rewrite of solution
author | Dominic Cleal <dominic@computerkb.co.uk> |
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date | Mon, 01 Dec 2008 19:11:55 +0000 |
parents | 0e08f4decf67 |
children |
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l = { } for a in range(2, 101): for b in range(2, 101): l[a**b] = None print len(l.keys())